Algebra 1 - Factoring Polynomials

Introduction

  • Factoring a polynomial means expressing it as a product of its factors.
  • For example, px=x4-2x3 can be expressed as px=x3x-2.
  • There are several methods of factoring polynomials. Some of them are described in the subsequent sections.

Factoring Polynomials by GCF

  • Factoring polynomials using this method can be accomplished in two steps.
    1. First, finding the greatest common factor (GCF) of all the terms.
    2. Then, rewrite the polynomial by taking out the GCF.
  • Let us understand this with the help of an example below.

Question: Factorize the polynomial px=3x2-6x.

Solution: 3x2=3·x·x and 6x=2·3·x

So, the GCF of 3x2-6x is 3x.

Now, 3x2-6x=3xx-2

  • In simple terms, this method is equivalent to the distributive property in reverse.

Factoring Polynomials by Grouping

  • In this method, the given polynomial is grouped in pairs to find the factors.
  • Let us understand this method through an example.

Question: Factorize the polynomial px=x4+3x3+3x+9.

Solution: px=x4+3x3+3x+9

=x4+3x3+3x+9

=x3x+3+3x+3

=x3+3x+3

  • Note: Sometimes, the terms need to be rearranged before grouping.

Factoring Polynomials by using Identities

  • This method can be applied to a polynomial expression that resembles one of the algebraic identities or can be modified to match with algebraic identities.
  • Some algebraic identities helpful in factoring polynomials are listed below.
    • x2-y2=x+yx-y
    • x3-y3=x-yx2+xy+y2
    • x3+y3=x+yx2-xy+y2
    • x2+2xy+y2=x+y2
    • x2-2xy+y2=x-y2
  • Let us factorize x2-25.

x2-25=x2-52=x+5x-5

Factoring Trinomials (Quadratic Polynomials)

  • The process of factoring trinomials of the general form px=x2+bx+c is explained through an example below.

Question: Factorize the polynomial, px=x2+10x-24

Solution: Since the first term is x2, we know that factoring will take the form.

x2+10x-24=x+   x+   

Now, we need to find two appropriate numbers for the blank spots.

When multiplied, these two numbers must yield -24 as a result and produce the coefficient of the middle term when added. The list of all the possible options are:

x-1x+24=x2+23x-24 (Incorrect)

x+1x-24=x2-23x-24 (Incorrect)

x+2x-12=x2-10x-24 (Incorrect)

x-2x+12=x2+10x-24 (Correct)

x-3x+8=x2+5x-24 (Incorrect)

x+3x-8=x2-5x-24 (Incorrect)

x-4x+6=x2+2x-24 (Incorrect)

x+4x-6=x2-2x-24 (Incorrect)

Thus the correct solution is x2+10x-24=x-2x+12.

  • Likewise, the process of factoring trinomials of the general form px=ax2+bx+c is explained through an example below.

Question: Factorize the polynomial, px=4x2+4x-3.

Solution: The coefficient of x2 term has more than one positive factor. Thus, the factoring can take one of the following forms.

4x2+4x-3=4x+   x+   

4x2+4x-3=2x+   2x+   

Now, we need to find two appropriate numbers for the blank spots.

When multiplied, these two numbers must yield -3 as a result and produce the coefficient of the middle term when added. The list of all the possible options are:

4x+1x-3=4x2-11x-3 (Incorrect)

4x-1x+3=4x2+11x-3 (Incorrect)

2x+12x-3=4x2-4x-3 (Incorrect)

2x-12x+3=4x2+4x-3 (Correct)

Thus the correct solution is 4x2+4x-3=2x-12x+3.

Cheat Sheet

  • The first approach for factoring polynomials should be to factor using the distributive property by taking the GCF out.
  • Polynomials in which terms can be rearranged & grouped, factoring by grouping approach can be used to find factors.
  • If the given polynomial can be modified to resemble any standard algebraic identities, factoring by using the identities method can be used.
  • Factoring quadratic polynomials means factoring them into two linear polynomials.

Blunder Areas

  • x2+y2x+y2
  • By factoring a polynomial, its value remains unchanged; only its form changes.